Optimal. Leaf size=492 \[ -\frac{5 a b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 d e^{3/2} \left (b^2-a^2\right )^{9/4}}+\frac{5 a b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 d e^{3/2} \left (b^2-a^2\right )^{9/4}}-\frac{\left (2 a^2+3 b^2\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{e \cos (c+d x)}}{d e^2 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)}}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{d e \left (a^2-b^2\right )^2 \sqrt{e \cos (c+d x)}}+\frac{b}{d e \left (a^2-b^2\right ) \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 d e \left (a^2-b^2\right )^2 \left (b-\sqrt{b^2-a^2}\right ) \sqrt{e \cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 d e \left (a^2-b^2\right )^2 \left (\sqrt{b^2-a^2}+b\right ) \sqrt{e \cos (c+d x)}} \]
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Rubi [A] time = 1.21853, antiderivative size = 492, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 12, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.48, Rules used = {2694, 2866, 2867, 2640, 2639, 2701, 2807, 2805, 329, 298, 205, 208} \[ -\frac{5 a b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 d e^{3/2} \left (b^2-a^2\right )^{9/4}}+\frac{5 a b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 d e^{3/2} \left (b^2-a^2\right )^{9/4}}-\frac{\left (2 a^2+3 b^2\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{e \cos (c+d x)}}{d e^2 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)}}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{d e \left (a^2-b^2\right )^2 \sqrt{e \cos (c+d x)}}+\frac{b}{d e \left (a^2-b^2\right ) \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 d e \left (a^2-b^2\right )^2 \left (b-\sqrt{b^2-a^2}\right ) \sqrt{e \cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 d e \left (a^2-b^2\right )^2 \left (\sqrt{b^2-a^2}+b\right ) \sqrt{e \cos (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 2694
Rule 2866
Rule 2867
Rule 2640
Rule 2639
Rule 2701
Rule 2807
Rule 2805
Rule 329
Rule 298
Rule 205
Rule 208
Rubi steps
\begin{align*} \int \frac{1}{(e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2} \, dx &=\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}+\frac{\int \frac{-a+\frac{3}{2} b \sin (c+d x)}{(e \cos (c+d x))^{3/2} (a+b \sin (c+d x))} \, dx}{-a^2+b^2}\\ &=\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}+\frac{2 \int \frac{\sqrt{e \cos (c+d x)} \left (-\frac{1}{2} a \left (a^2+4 b^2\right )-\frac{1}{4} b \left (2 a^2+3 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)} \, dx}{\left (a^2-b^2\right )^2 e^2}\\ &=\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}-\frac{\left (5 a b^2\right ) \int \frac{\sqrt{e \cos (c+d x)}}{a+b \sin (c+d x)} \, dx}{2 \left (a^2-b^2\right )^2 e^2}-\frac{\left (2 a^2+3 b^2\right ) \int \sqrt{e \cos (c+d x)} \, dx}{2 \left (a^2-b^2\right )^2 e^2}\\ &=\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}+\frac{\left (5 a^2 b\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{4 \left (a^2-b^2\right )^2 e}-\frac{\left (5 a^2 b\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{4 \left (a^2-b^2\right )^2 e}-\frac{\left (5 a b^3\right ) \operatorname{Subst}\left (\int \frac{\sqrt{x}}{\left (a^2-b^2\right ) e^2+b^2 x^2} \, dx,x,e \cos (c+d x)\right )}{2 \left (a^2-b^2\right )^2 d e}-\frac{\left (\left (2 a^2+3 b^2\right ) \sqrt{e \cos (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx}{2 \left (a^2-b^2\right )^2 e^2 \sqrt{\cos (c+d x)}}\\ &=-\frac{\left (2 a^2+3 b^2\right ) \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right )^2 d e^2 \sqrt{\cos (c+d x)}}+\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}-\frac{\left (5 a b^3\right ) \operatorname{Subst}\left (\int \frac{x^2}{\left (a^2-b^2\right ) e^2+b^2 x^4} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{\left (a^2-b^2\right )^2 d e}+\frac{\left (5 a^2 b \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{4 \left (a^2-b^2\right )^2 e \sqrt{e \cos (c+d x)}}-\frac{\left (5 a^2 b \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{4 \left (a^2-b^2\right )^2 e \sqrt{e \cos (c+d x)}}\\ &=-\frac{\left (2 a^2+3 b^2\right ) \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right )^2 d e^2 \sqrt{\cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 \left (a^2-b^2\right )^2 \left (b-\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 \left (a^2-b^2\right )^2 \left (b+\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}+\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}+\frac{\left (5 a b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e-b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{2 \left (a^2-b^2\right )^2 d e}-\frac{\left (5 a b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e+b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{2 \left (a^2-b^2\right )^2 d e}\\ &=-\frac{5 a b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{2 \left (-a^2+b^2\right )^{9/4} d e^{3/2}}+\frac{5 a b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{2 \left (-a^2+b^2\right )^{9/4} d e^{3/2}}-\frac{\left (2 a^2+3 b^2\right ) \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right )^2 d e^2 \sqrt{\cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 \left (a^2-b^2\right )^2 \left (b-\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{5 a^2 b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 \left (a^2-b^2\right )^2 \left (b+\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}+\frac{b}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)} (a+b \sin (c+d x))}-\frac{5 a b-\left (2 a^2+3 b^2\right ) \sin (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt{e \cos (c+d x)}}\\ \end{align*}
Mathematica [C] time = 6.63914, size = 777, normalized size = 1.58 \[ \frac{\cos ^{\frac{3}{2}}(c+d x) \left (\frac{12 \left (4 a \left (a^2-b^2\right ) \sin (c+d x)-\left (2 a^2 b+3 b^3\right ) \cos (2 (c+d x))-6 a^2 b+b^3\right )}{\left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)}}-\frac{\sin (c+d x) \left (a+b \sqrt{\sin ^2(c+d x)}\right ) \left (-\frac{\left (2 a^2+3 b^2\right ) \csc (c+d x) \left (8 b^{5/2} \cos ^{\frac{3}{2}}(c+d x) F_1\left (\frac{3}{4};-\frac{1}{2},1;\frac{7}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )+3 \sqrt{2} a \left (a^2-b^2\right )^{3/4} \left (-\log \left (-\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}+b \cos (c+d x)\right )+\log \left (\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}+b \cos (c+d x)\right )+2 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}+1\right )\right )\right )}{\sqrt{b} \left (b^2-a^2\right )}-\frac{48 a \left (a^2+4 b^2\right ) \left (\frac{a \cos ^{\frac{3}{2}}(c+d x) F_1\left (\frac{3}{4};\frac{1}{2},1;\frac{7}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )}{3 \left (a^2-b^2\right )}+\frac{\left (\frac{1}{8}+\frac{i}{8}\right ) \left (-\log \left (-(1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}+i b \cos (c+d x)\right )+\log \left ((1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}+i b \cos (c+d x)\right )+2 \tan ^{-1}\left (1-\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}\right )-2 \tan ^{-1}\left (1+\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}\right )\right )}{\sqrt{b} \sqrt [4]{b^2-a^2}}\right )}{\sqrt{\sin ^2(c+d x)}}\right )}{(a-b)^2 (a+b)^2}\right )}{24 d (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 10.079, size = 8216, normalized size = 16.7 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \cos \left (d x + c\right )\right )^{\frac{3}{2}}{\left (b \sin \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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